Help with Venn Diagrams?... I think...?

Ok they way this question is asked I am not sure if I am geting the right answer...





A market survey is conducted to determine whether a sports store should carry expensive training equipment for Skiers.





The proportions of people who participate in Skiiing, Skating, and racquet sports are as follows...





Skiing 0.40


Skating 0.55


Racquet Sports 0.35


Skiing and Skating 0.05


Skiing and Racquet Sports 0.15


Skating and Racquet Sports 0.15


All 3 0.05





What is the probability that a person chosen at random does Skiing?








So I got 0.40 - (0.15+0.05+0.05) = 0.15 are just skiers





After that I am stuck becuase the figures I used in my venn diagram do not add up to 1.00 which I am assuming to be 100% ..... ? Nor do the 3 Sports... Help

Help with Venn Diagrams?... I think...?
It should be 0.25





This is what you should have:





Just skiing = 0.4-(0.05+0.15-0.05) = 0.25





Just skating = 0.55-(0.05+.015-0.05)=0.40





Just racquet sports = 0.35-(0.15+0.15-0.05)=0.1





(0.25+0.4+0.1) + (0.15+0.15+0.05+0.05) - (3*0.05)= 1


0.75+0.4-0.15 =1 Correct.





Suppose you have just 2 intersecting sets A and B, then:





P(only A) = P(A) - P(AnB)





If you have 3 sets A,B,C then:





P(only A) = P(A) - P(AnB) - P(AnC) + P(BnC)
Reply:plz rewrite the whole question in exact words, if you need to make a new question for it, call it "venn diagrams"
Reply:The figures add up to higher than 1 and all the probablities of an event must be 1 (P(A) + P(not A)=1). So most likely there was an error in constructing the Venn diagram Rember to work from the inside out and pay attention to the areas that overlap.